Find the limit of the function by using direct substitution. limit as x approaches one of quantity x squared plus three x minus one.

Answer:Limit = -1Step-by-step explanation:We are given the following function:[tex]x^2 + 3x -1[/tex]We are to calculate the limit of this function as x approaches zero. For that, we will use direct substitution method and substitute the x with 0 in the given function to calculate its limit as follows:[tex] x ^ 2 + 3 x - 1 [/tex][tex] ( 0 ) ^ 2 + 3 ( 0 ) - 1 = - 1 [/tex]Therefore, the limit is -1.