Suppose that we have a white urn containing five white balls and one red ball and we have a red urn containing one white ball andfour red balls. An experiment consists of selecting at random a ball from the white urn and then (without replacing the first ball) selecting at random a ball from the urn having the color of the first ball. Find the probability that the second ball is red. What is the probability that the second ball is red is?

Answer:0.36[tex][/tex]Step-by-step explanation:here there are two situation1. from white urn the first ball chosen is whiteP(probability of first ball white)= 4/5now P( second ball red) = 1/5total probability of second ball being red = (4/5)*(1/4)= 4/202. from the white urn first ball chosen is redP(first ball red )= 1/5now, P(second ball red from red urn)= 4/5total probability of second ball being red = (1/5*4/5)= 4/25now considering both the situation the total probability that the second ball is red= 4/20 + 4/25 = 9/25= 0.36